Hi,
I think my answer may have been a little too quick. Seeing the
replies I realize that I was not really concentrated. Mark asked, -
what is an outgoing axle? Well that is Swenglish (a mix between
Swedish and English) for the outgoing shaft in the steering box. I
also didn4t notice that you wrote 1 and 2/3. I read it as 2/3. Now
when I can see clearer I think that the difference between your
revolutions to the left and the right just might be correct. I don4t
remember the exact difference but I recall that there always is one.
Probably due to the design of the worm. On the king pins there are
two small triangular stops on each side located at the bottom. If
both wheels on each side turn to lock on these stops you should be
fine otherwise there might be a problem. Please let me know if that
is the case.
Magnus Karlsson
Sweden
23 dec 2005 kl. 23.37 skrev Richard Bittmann:
> Hi Magnus, Thanks for your reply. As I recall, the steering and
> Idler arms are adjustable by 1/4 revolutions due to wider splines
> at those locations. Do you think I'm off by that far? Wouldn't 1/4
> turn throw everything off too far? I haven't set the cross rod
> length finally but now have it set so that the center to center
> dimension is 22 1/8". What do you think now? Richard Bittmann
>
> ----- Original Message ----- From: "Magnus Karlsson"
> <magnuskarlsson@bornet.net>
> To: "Healey Lista" <healeys@autox.team.net>
> Sent: Friday, December 23, 2005 1:19 PM
> Subject: Re: steering question
>
>
>> Sounds to me like you positioned the steering arm in the wrong
>> position on the outgoing axle.
>>
>> Magnus Karlsson
>> Sweden
>> 23 dec 2005 kl. 21.50 skrev Richard Bittmann:
>>
>>> Hello All,
>>> I just finished my steering restoration and when I turn the
>>> steering wheel
>>> lock to lock I get 1 2/3 revolutions to the left and 1 1/4
>>> revolutions to the
>>> right. What did I do wrong?? Richard Bittmann BJ7
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