Subject: Re: [Healeys] driving/fog lights
Hello Al,
Not sure which formula you are using to calculate the current draw, however;
the correct formula is : W (Wattage) = V (Volts) x I (Amperage).
Assuming you have 55 watt headlights (if not just change the number in the
equation) and switch on both auxilliary lights at the same time and
transposing for I gives
I = 48+48+55+55 / 13.6 which equals 15.15 Amps (206/13.6) which a generator
is capable of producing and well within the limits of an alternator.
Regards,
Norman
59 BN7
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