It's probably working right, hot is a very subjective term but they do get
exteremely warm. Amp draw on my fresh air (a 12 V motor) was about 4 amps as I
recall. That's 16 watts when drawn through a 1 ohm resistor. That'll get your
attention. Your motor is a 6 V which means it would draw more than mine. If we
use mine as a reference and assume that they all present about the same load
(somewhat of a leap of faith) then yours would draw 8 amps (mine =12V x 4 amps
for 48 watts so yours would be 6V x 8 amps for 48 watts. That would mean the 1
ohm would dissipate about 64 watts ( 8amps x 8amps x
1ohm). If your reducer has a greater rating than that you are ok. But even so
it would be like putting your hand to a 60 watt light bulb..HOT!!
For more on this type of thing you can see my webpage which has an electricity
section that explains this in more detail.
http://members.tripod.com/~oltruck
Bill
Samsred72@aol.com wrote:
> I have a question pertaining to reducing the voltage to the heater motor. I
>have a reducer in the line now that looks like a long cylindrical and hollow
>ceramic tube. It states on it... Clarostat VP-50-K 1ohm. If this is the proper
>reducer it seems to be working improperly. As the fan is drawing current this
>reducer gets hot enough to burn you quickly. I don't think it is heavy enough
>to carry the amps required by the motor. If so, can anyone tell me the amp
>draw of the "fresh air heater" motor so that I can get the proper reducer
>without taking off the cover... it's cold out side ya know?
>
> Sam
> '49 3100 Chevy
> oletrucks is devoted to Chevy and GM trucks built between 1941 and 1959
--
Bill Bailey
57 Chevrolet 3100
http://members.tripod.com/~oltruck/
oletrucks is devoted to Chevy and GM trucks built between 1941 and 1959
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