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## how to measure what you do

 To: triumphs how to measure what you do "Arthur H. Smith" Tue, 12 Jan 1999 11:35:38 -0500
 ```***from the jag list*** Someone asked if a person who does not drink beer can actually perform a "0 Beer" job on a car. He he he... how naive we are! It's not that simple my friend. Note that I've removed the tag from this topic as any discussion about beer is certainly not a waste of anything. Now, think about the scientific definition of "Work," and stay with me on this: The average (non-light) beer has 167 calories. A 6 -pack therefore has 1000 calories (1 kilo calorie - 1 kcal)1 kcal = 3.97 Btu. We don't like to think of British things when we work on our cars, so we convert 3.97 Btu to 0.001163 kW hours. 0.001163 kWh = 0.00156 hp (now we're talkin' - HORSEPOWER) 0.00156 hp = 51.48 lb-ft/min (0.00156*33,000) Now, for example, an E36 BMW has 20 lug nuts. If each is to be torqued to 74 lb-ft to accomplish the mounting of a set of R1s,that's 1480 lb-ft total. If performed in an hour, that's 1480/60 which equals 24.67 lb-ft/min. Now, divide our expended energy of 24.57 lb-ft/min by a six pack's rating of 51.48 lb-ft/min and you get .478 six-pack, or roughly 3 beers. Yes, mounting R1s for the next day's autocross is typically a three beer job. Knowing that energy cannot be created or destroyed, you HAVE to drink three beers to accomplish this job or the universe will be out of balance. Of course, you can eat a Powerbar to balance the universal forces, but the fact remains that mounting four tires will ALWAYS have the Pilsner Energy Equivalent (or, PEE rating) of three beers. So you see, each job we perform on the car will have it's own PEE rating whether you drink beer or not. The fact that you don't drink beer does not change the reality that a certain job expends the equivalent energy of a fixed amount of beer - there's no short cutting the laws of physics here. the arthur 69 GT6 in many many boxes (does that make it a kit car) 82 XJ6 hibernating 93 ford box ```
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