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1. RE: Ray's Air Compressor thread (score: 1): Author: sflatt@gislab.teale.ca.gov (Steve Flatt); Date: Wed, 11 Dec 1996 11:03:19 -0800; Assuming you put two compressors in parallel giving you maybe 20CFM, how do you ensure that you really deliver maximum volume to the tool in use? Is it simply a matter of using the largest diameter p; /html/shop-talk/1996-12/msg00036.html (7,187 bytes)
2. RE: Ray's Air Compressor thread (score: 1): Author: "W. R. Gibbons" <gibbons@northpole.med.uvm.edu>; Date: Wed, 11 Dec 1996 17:26:36 -0500 (EST); I think that's it. If you want 20 cfm and you have restrictions causing high resistance to flow, you either have to increase the pressure enough to force 20 cfm through to the tool you are using, or; /html/shop-talk/1996-12/msg00040.html (8,155 bytes)
3. RE: Ray's Air Compressor thread (score: 1): Author: jblair@exis.net (John T. Blair); Date: Wed, 11 Dec 1996 18:26:12 -0500; Within reason. Infact, if you plump you garage with 2" copper pipe you also get a nice increase to your storage supply. IMHO, definetly. The flow rate should be proportional to the cross sectional ar; /html/shop-talk/1996-12/msg00041.html (7,522 bytes)
4. RE: Ray's Air Compressor thread (score: 1): Author: "W. R. Gibbons" <gibbons@northpole.med.uvm.edu>; Date: Thu, 12 Dec 1996 00:15:08 -0500 (EST); I have to disagree. The aggregate resistance between the compressor and the tool is what limits the flow, just as the total resistance in an electrical circuit limits the current. If you have one sma; /html/shop-talk/1996-12/msg00044.html (8,133 bytes)
5. RE: Ray's Air Compressor thread (score: 1): Author: jblair@exis.net (John T. Blair); Date: Thu, 12 Dec 1996 15:59:17 -0500; Good point Ray John John T. Blair WA4OHZ email: jblair@exis.net Va. Beach, Va Phone: (757) 495-8229 48 TR1800 48 #4 Midget 65 Morgan 4/4 Series V 75 Bricklin SV1 77 Spitfire The one with the most toy; /html/shop-talk/1996-12/msg00045.html (7,208 bytes)

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