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References: [ +subject:/^(?:^\s*(re|sv|fwd|fw)[\[\]\d]*[:>-]+\s*)*Stopping\s+Power\s*$/: 16 ]

Total 16 documents matching your query.

1. Stopping Power (score: 1): Author: Alvin and Lucille Johnson <johnson@ids.net>; Date: Sat, 17 Oct 1998 08:52:02 -0400; The guy who bought my Tiger believes that the stopping power is not equal to the "GO" power. He wants to convert to rear discs, and maybe better calipers up front, and still run the 13" Panasports ri; /html/tigers/1998-10/msg00275.html (7,415 bytes)
2. Re: Stopping Power (score: 1): Author: Bob Palmer <rpalmer@ames.ucsd.edu>; Date: Sat, 17 Oct 1998 08:56:06 -0700; Al, et Listers, "Go see Dale, go see Dale, go see Dale" (Akuszewski that is). And bring money - lots of it. Vented rotors up front, Fiat calipers in the back and the NO (New Owner) will be stopping w; /html/tigers/1998-10/msg00279.html (8,413 bytes)
3. Re: Stopping Power (score: 1): Author: steve sage <rootes@ix.netcom.com>; Date: Sun, 18 Oct 1998 21:34:31 -0700; /html/tigers/1998-10/msg00306.html (9,924 bytes)
4. Re: Stopping Power (score: 1): Author: RSpontelli@aol.com; Date: Wed, 21 Oct 1998 00:03:02 EDT; << The question I am addressing is how do they work in real world conditions, repeated stop and go and stopping and panic stops to avoid accidents. In these cases, the standard setup does nowhere nea; /html/tigers/1998-10/msg00348.html (8,223 bytes)
5. Stopping Power (score: 1): Author: "Jay Laifman" <Jay_Laifman@countrywide.com>; Date: Wed, 21 Oct 1998 08:06:47 -0700; why BIGGER slaves give LESS braking! Bigger slaves means it needs MORE fluid to move the same distance. Therefore, you reduced the effectiveness of the rear brakes relative to the front brakes. Jay L; /html/tigers/1998-10/msg00365.html (8,409 bytes)
6. Re: Stopping Power (score: 1): Author: Bob Palmer <rpalmer@ames.ucsd.edu>; Date: Wed, 21 Oct 1998 09:52:23 -0700; Back to Mechanics 1A for you Jay. Turn to Chapter I, Page 2; F = pA That's force (on your brakes in this case) is equal to the product of area (that's pi times the radius of the slave piston squared; /html/tigers/1998-10/msg00366.html (9,286 bytes)
7. RE: Stopping Power (score: 1): Author: Theo Smit <TSmit@novatel.ca>; Date: Wed, 21 Oct 1998 10:53:08 -0600; The force produced by a piston is the area of the piston times the fluid pressure. Your pedal sinks (farther? further?) more, but the same pedal pressure gets you more rear brakes if you put more pis; /html/tigers/1998-10/msg00367.html (9,271 bytes)
8. Re: Stopping Power (score: 1): Author: Bob Palmer <rpalmer@ames.ucsd.edu>; Date: Wed, 21 Oct 1998 11:48:32; Maybe you are on the wrong side of the rostrum, Jay. As they say, "this is not rocket science" here; just simple mechanics. Crack an engineering book, take a Vallium, and call me in the morning. Bob; /html/tigers/1998-10/msg00370.html (8,059 bytes)
9. Re: Stopping Power (score: 1): Author: "Jay Laifman" <Jay_Laifman@countrywide.com>; Date: Wed, 21 Oct 1998 10:16:48 -0700; You are onthe wrong side of the fulcrum. Bob Palmer <rpalmer@ames.ucsd.edu> on 10/21/98 09:52:23 AM Jay, Back to Mechanics 1A for you Jay. Turn to Chapter I, Page 2; F = pA That's force (on your brak; /html/tigers/1998-10/msg00371.html (9,531 bytes)
10. Re: Stopping Power (score: 1): Author: "Jay Laifman" <Jay_Laifman@countrywide.com>; Date: Wed, 21 Oct 1998 10:41:21 -0700; I take back my second comment about leverage. However, it seems to me that since the calipers are not changing, that relative to the rear brakes, the rears will now move less than the fronts for the; /html/tigers/1998-10/msg00372.html (9,929 bytes)
11. Re: Stopping Power (score: 1): Author: Bob Palmer <rpalmer@ames.ucsd.edu>; Date: Wed, 21 Oct 1998 12:25:01; Consulted a higher authority? Yes, but so what? Rate isn't a factor here Jay, unless your talking about the reaction time before the brakes take hold. That's why Rich likes to keep his rear brakes ti; /html/tigers/1998-10/msg00373.html (8,711 bytes)
12. RE: Stopping Power (score: 1): Author: Theo Smit <TSmit@novatel.ca>; Date: Wed, 21 Oct 1998 13:25:40 -0600; They will move as far as they can until the pressure in the system is equalized, i.e. p = F/A results in the same "p" for all four calipers, and the master cylinder as well. So for any caliper, if yo; /html/tigers/1998-10/msg00374.html (11,361 bytes)
13. Re: Stopping Power (score: 1): Author: DrMayf@aol.com; Date: Wed, 21 Oct 1998 15:39:09 EDT; Ain't so! If the force remains constant and the area gets bigger, pressure ex: F = p x a let F = 10, a = 2, then p = 10 / 2 = 5 now let F = 10, a = 4, then p = 10 / 4 = 2.5 Smaller piston area equals; /html/tigers/1998-10/msg00375.html (7,666 bytes)
14. RE: Stopping Power (score: 1): Author: Theo Smit <TSmit@novatel.ca>; Date: Wed, 21 Oct 1998 13:57:09 -0600; Your math is impeccable, as usual, but you should specify _which_ piston needs to be large to move the slave a lot. Be careful, now...; /html/tigers/1998-10/msg00376.html (8,145 bytes)
15. RE: Stopping Power (score: 1): Author: Bob Palmer <rpalmer@ames.ucsd.edu>; Date: Wed, 21 Oct 1998 13:04:44; Once again we prove there's no such thing as a simple, non-controversial question in this crowd. I hope you have an especially good Chance card handy for Larry - I think your gonna need it. Bob need; /html/tigers/1998-10/msg00378.html (8,052 bytes)
16. Re: Stopping Power (score: 1): Author: Mark <markr@advdata.net>; Date: Wed, 21 Oct 1998 17:43:59 -0400; Theo is on the money. Pressure is, for all practical purposes, equal the brake system at all times. BTW, the name of the field that deals with this subject matter is "hydrostatics" not "fluid dynamic; /html/tigers/1998-10/msg00379.html (8,823 bytes)

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