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References: [ +subject:/^(?:^\s*(re|sv|fwd|fw)[\[\]\d]*[:>-]+\s*)*The\s+REAL\s+ANSWER\-Riddle\s+me\s+this\.\.\.\.\.\s+\(little\s+LBC\)\s*$/: 4 ]

Total 4 documents matching your query.

1. Re: The REAL ANSWER-Riddle me this..... (little LBC) (score: 1)
Author: Ronsoave@aol.com
Date: Sat, 10 Apr 1999 23:24:38 EDT
Me too. But I must jump in (and I swore I wouldn't) - the average speed would be distance traveled divided by the time to get there, so if you're going 30 and then 90, 2 miles in 2.75 minutes = avg s
/html/spridgets/1999-04/msg00501.html (8,225 bytes)

2. Re: The REAL ANSWER-Riddle me this..... (little LBC) (score: 1)
Author: Frank Clarici <spritenut@Exit109.com>
Date: Sat, 10 Apr 1999 23:45:40 -0400
More math and... Keith Moon yesterday, Einstein today. Please note both these guys are dead. And as far as Einstein goes, my grandfather used to go fishing with the man, he'll tell you the guy was an
/html/spridgets/1999-04/msg00502.html (8,561 bytes)

3. Re: The REAL ANSWER-Riddle me this..... (little LBC) (score: 1)
Author: Ronsoave@aol.com
Date: Sat, 10 Apr 1999 23:43:36 EDT
He'd have gotten the riddle, though.
/html/spridgets/1999-04/msg00503.html (7,593 bytes)

4. Re: The REAL ANSWER-Riddle me this..... (little LBC) (score: 1)
Author: "Keith Turk" <kturk@ala.net>
Date: Sun, 11 Apr 1999 03:42:28 -0700
ahhh but wait.... at the end of the second mile would we have to deal with E=MC2?.... I mean if there was say a block wall signifying the end of the two mile mark.. what then.... Keith Moon would wan
/html/spridgets/1999-04/msg00506.html (8,384 bytes)


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