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1. speed vs hp question (score: 1): Author: "Jack W. Drews" <vinttr4@geneseo.net>; Date: Tue, 10 Aug 2004 10:07:45 -0500; Assume for a moment that you have a car with a known hp at the rear wheels, and you also know the top speed attainable with that car. Does anybody know the math for determining how many additional hp; /html/fot/2004-08/msg00083.html (6,878 bytes)
2. RE: speed vs hp question (score: 1): Author: "Randall Young" <Ryoung@navcomtech.com>; Date: Tue, 10 Aug 2004 08:55:41 -0700; It's a cube law, so it depends on what your original top speed was and how much you try to increase it. The formula, roughly, is New Required Power = (New Speed/Old Speed)^3 * Old Power Thus, if you; /html/fot/2004-08/msg00086.html (7,345 bytes)
3. Re: speed vs hp question (score: 1): Author: Henry Frye <henry@henryfrye.com>; Date: Tue, 10 Aug 2004 12:53:44 -0400; Hmmmm. No, I don't know the math, but I am wondering why you want to know this! Might need to take an extra careful look at New Blue next week!; /html/fot/2004-08/msg00088.html (7,211 bytes)
4. Re: speed vs hp question (score: 1): Author: Don Elliott <58tr3a@videotron.ca>; Date: Tue, 10 Aug 2004 14:22:31 -0400; I think it's all another ruse by Uncle Jack to instill a new sort of fear into all you other TR racers so he can win while you all worry. Don Elliott; /html/fot/2004-08/msg00090.html (7,658 bytes)
5. Re: speed vs hp question (score: 1): Author: "Jack W. Drews" <vinttr4@geneseo.net>; Date: Tue, 10 Aug 2004 15:00:32 -0500; Dang, I can't seem to get away with anything any more. uncle jack; /html/fot/2004-08/msg00093.html (6,970 bytes)
6. RE: speed vs hp question (score: 1): Author: Bill Babcock <BillB@bnj.com>; Date: Wed, 11 Aug 2004 00:21:02 -0700; Close enough. Drag is proportional to the cube of speed, rolling resistance is linear, and so is drive train resistance (except crank windage). You'd wind up with some complex number for a given car,; /html/fot/2004-08/msg00111.html (8,153 bytes)

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