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Re: [Healeys] Right triangle dimension needed

To: John Sims <ahbn6@verizon.net>, 'Ed's Shop' <shop@justbrits.com>,
Subject: Re: [Healeys] Right triangle dimension needed
From: <pennell@cox.net>
Date: Wed, 1 Apr 2009 19:17:01 -0400
And John it always handy to remember the rule of 3,4,5.  3 squared + 4 squared 
= 5 squared.  Helps to easily check things for square and applicable in any 
unit.

Keith Pennell

---- John Sims <ahbn6@verizon.net> wrote: 
> I come up with 6 also The proof is the  Pythagorean Theorem where you take
> the square root of the sum of the square of the horizontal side plus the
> square of the base with the answer being the hypotenuse. One side being 6 -
> 36, one side being 8 = 64 the sum of which is 100 and the square root of
> which is 10. Thus the missing number is 6.
> 
> That is the OLD math - Ed -- several thousands of years old. And, still
> holds true today. See: http://en.wikipedia.org/wiki/Pythagorean_theorem
> John Sims, BN6
> Aberdeen, NJ
>  
> www.healey6.com
> 
> -----Original Message-----
> From: healeys-bounces@autox.team.net [mailto:healeys-bounces@autox.team.net]
> On Behalf Of Ed's Shop
> Sent: Wednesday, April 01, 2009 7:50 PM
> To: healeys@autox.team.net
> Subject: Re: [Healeys] Right triangle dimension needed
> 
> <<    6
> Cheers.......Bob>>
> 
> Sorry but NO, Bob !!!
> 
> "Down" here 'New Math' is still taught in some of 
> our lower level (age wise) schools and therefore 
> the answer IS:
> 
> 33 1/3 !!!
> 
> Regards...
> 
> Ed
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