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Re: [Spridgets] Bentley-RR Trivia: was calculating speed

To: "Kitterer Bob" <bkitterer@mac.com>, "Spridget List"
Subject: Re: [Spridgets] Bentley-RR Trivia: was calculating speed
From: "Hal Faulkner" <hal@katemuir.com>
Date: Tue, 21 Oct 2008 17:19:06 -0700
Bob,
Circumference of 10" wheel is 31.4159.... inches (10 pi)
Circumference of a 20 inch wheel is     62.82318 (20 pi = 2(10 pi))
Hal

-----Original Message-----
From: spridgets-bounces@autox.team.net
[mailto:spridgets-bounces@autox.team.net]On Behalf Of Kitterer Bob
Sent: Tuesday, October 21, 2008 4:46 PM
To: Spridget List
Subject: Re: [Spridgets] Bentley-RR Trivia: was calculating speed


Going from 10 to 20 inch wheels at the same rpm will be three times  
as fast  not twice - C= pi D  :-0

Bob Kitterer

1960 Austin Healey Sprite (Mk IV in disguise)
1966 Austin Healey Sprite Mk III (Trevor) - still in boxes
2000 Miata Special Edition




On Oct 21, 2008, at 11:58 AM, Lester wrote:

> For example a 20 hp bike motor that will turn 6000 revs (and  
> pretending that the tranny is direct drive) will turn the tires  
> 6000 revs.  If those are 10 inch circumference tires then the bike  
> will go speed x,(no, I'm not going to calculate it out.) but if you  
> have 20 inch circumference tires then the bike will go twice as  
> fast *** IF *** it is not limited by drag and that the engine can  
> turn the 20 inch circumference tires at 6000 revs.
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