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Why does increasing the rocker ratio cause a need for more clearance?
Sent from my keyboard
> On Oct 31, 2015, at 6:14 PM, Michael Rowe via Spridgets <spridgets@autox.t=
eam.net> wrote:
>=20
> I used Minisport roller rockers bought cheap in the 2008-9 crash. I no lo=
nger remember, but they probably are 1.5 (red), and I also used a "warm" Elg=
in cam that came in a box of parts.
> =20
> Where higher ratio rockers are to be used, the required valve clearance ca=
n then be assessed using this simple formula. For instance when using 1.5 ro=
ckers, you obviously need to multiply the cam/follower clearance by 1.5. So 0=
.010-in x 1.5 gives 0.015-in for standard/mild cams and 0.012-in x 1.5 gives=
0.018-in for race/more-modified cams. Interestingly, most re-profiled perfo=
rmance cams generally have a suggested valve clearance of 0.016-in with stan=
dard ratio rockers. To assess required valve clearance where higher ratio ro=
ckers are used simply work it backwards and multiply by the higher ratio. Th=
is works out as 0.016-in divided by 1.25 =3D 0.0128, then x 1.5 =3D 0.0192" -=
or 0.019" at the valve.
> ----- Original Message -----
> From: Michael MacLean
> To: Rick Fisk ; Michael Rowe
> Cc: Spridgets
> Sent: Saturday, October 31, 2015 4:49 PM
> Subject: Re: [Spridgets] rocker clearance
>=20
> How about when you have 1.5 rocker arms? Drove the Bugeye around yesterda=
y. Runs great, still blue smoke on acceleration on a recent rebuild. At le=
at 1000 miles since rebuild. I'm afraid the rings never seated properly. N=
ot sure of the cylinder wall surface during the rebuild as I did not so that=
part of it.
> Mike MacLean
>=20
>=20
>=20
> On Saturday, October 31, 2015 1:26 PM, Rick Fisk via Spridgets <spridgets@=
autox.team.net> wrote:
>=20
>=20
> The 0.029 in. spec is a whole different thing used when you are assembling=
the engine. If your engine is together and you just want to set the valve c=
learance it should be 0.012 in. set cold.
>=20
> Sent from my keyboard
>=20
>> On Oct 31, 2015, at 4:06 PM, Michael Rowe via Spridgets <spridgets@autox.=
team.net> wrote:
>>=20
>=20
> New 1275 engine.
> Haynes says "Rocker clearance, timing only =3D 0.029 in.
> My mechanic/tutor says, "that is twice what it should be."
> Bentley says:
> Rocker clearance: Running (Standard) =3D 0.012 in. cold
> Running (competition work) =3D 0.015 in.
> timing =3D 0.029 in.
> Online sites agree on =3D .012 in. cold.
> =20
> So what is the 0.029 in. for?
> =20
> Michael Rowe
>> ------------------------
>>=20
>> spridgets@autox.team.net
>>=20
>> Donate: http://www.team.net/donate.html
>> Suggested annual donation: $12.75
>>=20
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k@chartermi.net
>=20
> ------------------------
>=20
> spridgets@autox.team.net
>=20
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>=20
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neer.mike@att.net
>=20
>=20
> ------------------------
>=20
> spridgets@autox.team.net
>=20
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>=20
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<html><head><meta http-equiv=3D"content-type" content=3D"text/html; charset=3D=
utf-8"></head><body dir=3D"auto"><div>Why does increasing the rocker ratio c=
ause a need for more clearance?<br><br>Sent from my keyboard</div><div><br>O=
n Oct 31, 2015, at 6:14 PM, Michael Rowe via Spridgets <<a href=3D"mailto=
:spridgets@autox.team.net">spridgets@autox.team.net</a>> wrote:<br><br></=
div><blockquote type=3D"cite"><div>
<meta content=3D"text/html; charset=3Dutf-8" http-equiv=3D"Content-Type">
<meta name=3D"GENERATOR" content=3D"MSHTML 9.00.8112.16708">
<div><font face=3D"Arial">I used Minisport roller rockers bought cheap i=
n the=20
2008-9 crash. I no longer remember, but they probably are 1.5=20
(red), and I also used a "warm" Elgin cam that came in a box of=20=
parts.</font></div>
<div><font face=3D"Arial"></font> </div>
<div><span>Where <a href=3D"http://www.spridgetmania.com/part/C-AHT436/=
Roller-Tipped-15-Ratio-Rockers-Aluminum">higher=20
ratio rockers</a> are to be used, the required valve clearance can then=
be=20
assessed using this simple formula. For instance when using 1.5 rockers, you=
=20
obviously need to multiply the cam/follower clearance by 1.5. So 0.010-in x 1=
.5=20
gives 0.015-in for standard/mild cams and 0.012-in x 1.5 gives 0.018-in for=20=
race/more-modified cams. Interestingly, most re-profiled performance cams=20=
generally have a suggested valve clearance of 0.016-in with standard ratio=20=
rockers. To assess required valve clearance where higher ratio rockers are u=
sed=20
simply work it backwards and multiply by the higher ratio. This works out as=
=20
0.016-in divided by 1.25 =3D 0.0128, then x 1.5 =3D 0.0192" - or 0.019" at t=
he=20
valve.</span></div>
<blockquote style=3D"BORDER-LEFT: #000000 2px solid; PADDING-LEFT: 5px; PADD=
ING-RIGHT: 0px; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px" dir=3D"ltr">
<div style=3D"FONT: 10pt arial">----- Original Message ----- </div>
<div style=3D"FONT: 10pt arial; BACKGROUND: #e4e4e4; font-color: black"><b=
>From:</b>=20
<a title=3D"rrengineer.mike@att.net" href=3D"mailto:rrengineer.mike@att.ne=
t">Michael=20
MacLean</a> </div>
<div style=3D"FONT: 10pt arial"><b>To:</b> <a title=3D"refisk@chartermi.ne=
t" href=3D"mailto:refisk@chartermi.net";>Rick Fisk</a> ; <a title=3D"mdrowe@o=
ptonline.net" href=3D"mailto:mdrowe@optonline.net";>Michael Rowe</a>=20
</div>
<div style=3D"FONT: 10pt arial"><b>Cc:</b> <a title=3D"spridgets@autox.tea=
m.net" href=3D"mailto:spridgets@autox.team.net";>Spridgets</a> </div>
<div style=3D"FONT: 10pt arial"><b>Sent:</b> Saturday, October 31, 2015 4:=
49=20
PM</div>
<div style=3D"FONT: 10pt arial"><b>Subject:</b> Re: [Spridgets] rocker=20
clearance</div>
<div><br></div>
<div style=3D"BACKGROUND-COLOR: #fff; FONT-FAMILY: times new roman, new yo=
rk, times, serif; COLOR: #000; FONT-SIZE: 16px">
<div id=3D"yui_3_16_0_1_1446323015003_17729">How about when you have 1.5 r=
ocker=20
arms? Drove the Bugeye around yesterday. Runs great, still blu=
e=20
smoke on acceleration on a recent rebuild. At leat 1000 miles since=20=
rebuild. I'm afraid the rings never seated properly. Not sure o=
f=20
the cylinder wall surface during the rebuild as I did not so that part of=20=
it.<br></div>
<div dir=3D"ltr" id=3D"yui_3_16_0_1_1446323015003_17730">Mike MacLean<br><=
/div>
<div id=3D"yui_3_16_0_1_1446323015003_17731"><span></span></div><br>
<div class=3D"qtdSeparateBR"><br><br></div>
<div style=3D"DISPLAY: block" class=3D"yahoo_quoted">
<div style=3D"FONT-FAMILY: times new roman, new york, times, serif; FONT-S=
IZE: 16px">
<div style=3D"FONT-FAMILY: HelveticaNeue, Helvetica Neue, Helvetica, Arial=
, Lucida Grande, sans-serif; FONT-SIZE: 16px">
<div dir=3D"ltr"><font size=3D"2" face=3D"Arial">On Saturday, October 31, 2=
015 1:26 PM,=20
Rick Fisk via Spridgets <<a href=3D"mailto:spridgets@autox.team.net";>sp=
ridgets@autox.team.net</a>>=20
wrote:<br></font></div>
<blockquote style=3D"BORDER-LEFT: rgb(16,16,255) 2px solid; MARGIN-TOP: 5p=
x; PADDING-LEFT: 5px; MARGIN-LEFT: 5px"><br><br>
<div class=3D"y_msg_container">
<div id=3D"yiv3068736433">
<div>
<div>The 0.029 in. spec is a whole different thing used when you are=20
assembling the engine. If your engine is together and you just wan=
t to=20
set the valve clearance it should be 0.012 in. set cold.<br clear=3D"non=
e"><br clear=3D"none">Sent from my keyboard</div>
<div id=3D"yiv3068736433yqt61360" class=3D"yiv3068736433yqt3461902488">
<div><br clear=3D"none">On Oct 31, 2015, at 4:06 PM, Michael Rowe via Sp=
ridgets=20
<<a href=3D"mailto:spridgets@autox.team.net"; shape=3D"rect" rel=3D"no=
follow" target=3D"_blank" ymailto=3D"mailto:spridgets@autox.team.net";>spridg=
ets@autox.team.net</a>>=20
wrote:<br clear=3D"none"><br clear=3D"none"></div>
<blockquote type=3D"cite">
<div></div></blockquote></div></div>
<div id=3D"yiv3068736433yqt64797" class=3D"yiv3068736433yqt3461902488">
<style></style>
</div>
<div>
<div id=3D"yiv3068736433yqt61805" class=3D"yiv3068736433yqt3461902488">
<div><font face=3D"Arial">New 1275 engine.</font></div>
<div><font face=3D"Arial">Haynes says "Rocker clearance, timing only=20
=3D 0.029 in.</font></div>
<div><font face=3D"Arial">My mechanic/tutor says, "that is twice what it=
should=20
be."</font></div>
<div><font face=3D"Arial">Bentley says:</font></div>
<div><font face=3D"Arial">Rocker clearance: Running (Standard) =3D 0.012=
in.=20
cold</font></div>
<div><font face=3D"Arial"> =20
&nb=
sp;=20
Running (competition work) =3D 0.0=
15=20
in.</font></div>
<div><font face=3D"Arial"> &nbs=
p; &n=
bsp; =20
timing =3D 0.029 in.</font></div>
<div><font face=3D"Arial">Online sites agree on =3D .012 in.=20=
cold.</font></div>
<div><font face=3D"Arial"></font> </div>
<div><font face=3D"Arial">So what is the 0.029 in. for?</font></div>
<div><font face=3D"Arial"></font> </div>
<div><font face=3D"Arial">Michael Rowe</font></div></div>
<blockquote type=3D"cite">
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pan><br clear=3D"none"><span><a href=3D"mailto:spridgets@autox.team.net"; sha=
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<div id=3D"yqt21911" class=3D"yqt3461902488">------------------------<br=
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</div></blockquote><blockquote type=3D"cite"><div><span>--------------------=
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