Subject: [Healeys] off topic rechargeable battery query

From: "Simon Lachlan" <[email-masked]>
Date: Thu, 4 Jun 2015 15:03:23 +0100

This is a multi-part message in MIME format.

--===============2518804976042608885==
	boundary="----=_NextPart_000_0133_01D09ED7.9B01D450"
Content-Language: en-gb

This is a multi-part message in MIME format.

------=_NextPart_000_0133_01D09ED7.9B01D450
	charset="us-ascii"
Content-Transfer-Encoding: 7bit

The string on 1.5v recharging demonstrated that some of you gurus are
multitalented(sp?). So............

The batteries in our domestic cordless phones are giving up.

They are AAA Nickel Metal Hydride 550mAh.

Looking on eBay, most similar rechargeable AAA phone batteries are around
1500mAh. Nothing less than 700mAh.

Can I stick in the highest rated that I can find, 1800mAh, and expect good
results? Or does the higher mAh level imply some level of something that the
phones' chargers won't manage???

(The charger says "Output: 6v. 150mAh")

Simon

------=_NextPart_000_0133_01D09ED7.9B01D450
	charset="us-ascii"
Content-Transfer-Encoding: quoted-printable

<html xmlns:v=3D"urn:schemas-microsoft-com:vml" =
xmlns:o=3D"urn:schemas-microsoft-com:office:office" =
xmlns:w=3D"urn:schemas-microsoft-com:office:word" =
xmlns:m=3D"http://schemas.microsoft.com/office/2004/12/omml" =
xmlns=3D"http://www.w3.org/TR/REC-html40"><head><meta =
http-equiv=3DContent-Type content=3D"text/html; =
charset=3Dus-ascii"><meta name=3DGenerator content=3D"Microsoft Word 12 =
(filtered medium)"><style><!--
/* Font Definitions */
@font-face
	{font-family:"Cambria Math";
	panose-1:2 4 5 3 5 4 6 3 2 4;}
@font-face
	{font-family:Calibri;
	panose-1:2 15 5 2 2 2 4 3 2 4;}
/* Style Definitions */
p.MsoNormal, li.MsoNormal, div.MsoNormal
	{margin:0cm;
	margin-bottom:.0001pt;
	font-size:11.0pt;
	font-family:"Calibri","sans-serif";}
a:link, span.MsoHyperlink
	{mso-style-priority:99;
	color:blue;
	text-decoration:underline;}
a:visited, span.MsoHyperlinkFollowed
	{mso-style-priority:99;
	color:purple;
	text-decoration:underline;}
span.EmailStyle17
	{mso-style-type:personal-compose;
	font-family:"Calibri","sans-serif";
	color:windowtext;}
.MsoChpDefault
	{mso-style-type:export-only;}
@page WordSection1
	{size:612.0pt 792.0pt;
	margin:72.0pt 72.0pt 72.0pt 72.0pt;}
div.WordSection1
	{page:WordSection1;}
--></style><!--[if gte mso 9]><xml>
<o:shapedefaults v:ext=3D"edit" spidmax=3D"1026" />
</xml><![endif]--><!--[if gte mso 9]><xml>
<o:shapelayout v:ext=3D"edit">
<o:idmap v:ext=3D"edit" data=3D"1" />
</o:shapelayout></xml><![endif]--></head><body lang=3DEN-GB link=3Dblue =
vlink=3Dpurple><div class=3DWordSection1><p class=3DMsoNormal>The string =
on 1.5v recharging demonstrated that some of you gurus are =
multitalented(sp?). So............<o:p></o:p></p><p =
class=3DMsoNormal>The batteries in our domestic cordless phones are =
giving up.<o:p></o:p></p><p class=3DMsoNormal>They are AAA Nickel Metal =
Hydride 550mAh.<o:p></o:p></p><p class=3DMsoNormal>Looking on eBay, most =
similar rechargeable AAA phone batteries are around 1500mAh. Nothing =
less than 700mAh.<o:p></o:p></p><p class=3DMsoNormal>Can I stick in the =
highest rated that I can find, 1800mAh, and expect good results? Or does =
the higher mAh level imply some level of something that the =
phones&#8217; chargers won&#8217;t manage???<o:p></o:p></p><p =
class=3DMsoNormal>(The charger says &#8220;Output: 6v. =
150mAh&#8221;)<o:p></o:p></p><p =
class=3DMsoNormal>Simon<o:p></o:p></p></div></body></html>
------=_NextPart_000_0133_01D09ED7.9B01D450--

--===============2518804976042608885==
Content-Transfer-Encoding: 7bit
Content-Disposition: inline

_______________________________________________
Archive: http://www.team.net/archive

[email-masked]
http://autox.team.net/mailman/listinfo/healeys

--===============2518804976042608885==--

---

From: Per Schoerner <[email-masked]>
Date: Thu, 4 Jun 2015 17:16:51 +0200

--===============9128824744593942712==
	boundary="_45B6A83A-7312-A35B-BAEF-F45BE7D76B02_"

--_45B6A83A-7312-A35B-BAEF-F45BE7D76B02_
Content-Transfer-Encoding: quoted-printable

Hi
Presumably there are 4 1.5 Volt cells in the phone that are connected in se=
ries. 4 * 1.5 =3D 6, voila.

Per

----- Ursprungligt meddelande -----
Fr=E5n: Bob Spidell
Skickat: 2015-06-04 16:40
Till: [email-masked]
=C4mne: Re: [Healeys] off topic rechargeable battery query

The mAH is a rating of how much current the battery can supply for how long=
:

 'milli Amp Hour'

 Get the highest rated you can find/afford; though the rating on the Chines=
e knock-offs--I think most of them are--seems to be overstated.  The load--=
how much current will be used--is determined by the circuit on the phone.

 The statement on the charger makes no sense; applying 6V to a 1.5V battery=
 would cook it in short order (putting 48V on a car battery would boil the =
electrolyte; creating a major mess and possibly an explosion).  I suspect i=
t's a nominal rating; i.e. it will put out 150mAH at 6v, but only needs abo=
ut, oh, 2V or less to charge the batteries and would supply 450mAH at that =
voltage.

 E (voltage) =3D I (current) * R (resistance).  Plug in any 2 known values-=
-and use a little algebra if necessary--and you'll get the third.

 Bob

On 6/4/2015 7:03 AM, Simon Lachlan wrote:

<!-- /* Font Definitions */ @font-face {font-family:"Cambria Math"; panose-=
1:2 4 5 3 5 4 6 3 2 4;} @font-face {font-family:Calibri; panose-1:2 15 5 2 =
2 2 4 3 2 4;} /* Style Definitions */ p.MsoNormal, li.MsoNormal, div.MsoNor=
mal {margin:0cm; margin-bottom:.0001pt; font-size:11.0pt; font-family:"Cali=
bri","sans-serif";} a:link, span.MsoHyperlink {mso-style-priority:99; color=
:blue; text-decoration:underline;} a:visited, span.MsoHyperlinkFollowed {ms=
o-style-priority:99; color:purple; text-decoration:underline;} span.EmailSt=
yle17 {mso-style-type:personal-compose; font-family:"Calibri","sans-serif";=
 color:windowtext;} .MsoChpDefault {mso-style-type:export-only;} @page Word=
Section1 {size:612.0pt 792.0pt; margin:72.0pt 72.0pt 72.0pt 72.0pt;} div.Wo=
rdSection1 {page:WordSection1;} -->

The string on 1.5v recharging demonstrated that some of you gurus are multi=
talented(sp?). So............

Looking on eBay, most similar rechargeable AAA phone batteries are around 1=
500mAh. Nothing less than 700mAh.

Can I stick in the highest rated that I can find, 1800mAh, and expect good =
results? Or does the higher mAh level imply some level of something that th=
e phones=92 chargers won=92t manage???

(The charger says =93Output: 6v. 150mAh=94)

Simon=

--_45B6A83A-7312-A35B-BAEF-F45BE7D76B02_
Content-Transfer-Encoding: quoted-printable

<html xmlns:o><head>=0A=
    <meta content=3D"text/html; charset=3Dwindows-1252" http-equiv=3D"Conte=
nt-Type">=0A=
  =0A=
  </head><body bgColor=3D"#ffffff" text=3D"#000000"><div><div style=3D"font=
-family: Calibri,sans-serif; font-size: 11pt;">Hi<br>Presumably there are 4=
 1.5 Volt cells in the phone that are connected in series. 4 * 1.5 =3D 6, v=
oila.<br><br>Per<br><br></div></div><hr><span style=3D"font-family: Tahoma,=
sans-serif; font-size: 10pt; font-weight: bold;">Fr=E5n: </span><span style=
=3D"font-family: Tahoma,sans-serif; font-size: 10pt;">Bob Spidell</span><br=
><span style=3D"font-family: Tahoma,sans-serif; font-size: 10pt; font-weigh=
t: bold;">Skickat: </span><span style=3D"font-family: Tahoma,sans-serif; fo=
nt-size: 10pt;">2015-06-04 16:40</span><br><span style=3D"font-family: Taho=
ma,sans-serif; font-size: 10pt; font-weight: bold;">Till: </span><span styl=
e=3D"font-family: Tahoma,sans-serif; font-size: 10pt;">[email-masked]=
et</span><br><span style=3D"font-family: Tahoma,sans-serif; font-size: 10pt=
; font-weight: bold;">=C4mne: </span><span style=3D"font-family: Tahoma,san=
s-serif; font-size: 10pt;">Re: [Healeys] off topic rechargeable battery que=
ry</span><br><br>=0A=
    The mAH is a rating of how much current the battery can supply for=0A=
    how long:<br>=0A=
    <br>=0A=
    'milli Amp Hour'<br>=0A=
    <br>=0A=
    Get the highest rated you can find/afford; though the rating on the=0A=
    Chinese knock-offs--I think most of them are--seems to be=0A=
    overstated.&nbsp; The load--how much current will be used--is determine=
d=0A=
    by the circuit on the phone.<br>=0A=
    <br>=0A=
    The statement on the charger makes no sense; applying 6V to a 1.5V=0A=
    battery would cook it in short order (putting 48V on a car battery=0A=
    would boil the electrolyte; creating a major mess and possibly an=0A=
    explosion).&nbsp; I suspect it's a nominal rating; i.e. it will put out=
=0A=
    150mAH at 6v, but only needs about, oh, 2V or less to charge the=0A=
    batteries and would supply 450mAH at that voltage.<br>=0A=
    <br>=0A=
    E (voltage) =3D I (current) * R (resistance).&nbsp; Plug in any 2 known=
=0A=
    values--and use a little algebra if necessary--and you'll get the=0A=
    third.<br>=0A=
    <br>=0A=
    Bob<br>=0A=
    <br>=0A=
    <br>=0A=
    <br>=0A=
    <div class=3D"moz-cite-prefix">On 6/4/2015 7:03 AM, Simon Lachlan=0A=
      wrote:<br>=0A=
    </div>=0A=
    <blockquote cite=3D"mid:013201d09ecf$393d6c50$abb844f0$@lachlan@homecal=
l.co.uk" type=3D"cite">=0A=
      =0A=
      <meta name=3D"Generator" content=3D"Microsoft Word 12 (filtered&#13;&=
#10;        medium)">=0A=
      <style><!--=0A=
/* Font Definitions */=0A=
@font-face=0A=
	{font-family:"Cambria Math";=0A=
	panose-1:2 4 5 3 5 4 6 3 2 4;}=0A=
@font-face=0A=
	{font-family:Calibri;=0A=
	panose-1:2 15 5 2 2 2 4 3 2 4;}=0A=
/* Style Definitions */=0A=
p.MsoNormal, li.MsoNormal, div.MsoNormal=0A=
	{margin:0cm;=0A=
	margin-bottom:.0001pt;=0A=
	font-size:11.0pt;=0A=
	font-family:"Calibri","sans-serif";}=0A=
a:link, span.MsoHyperlink=0A=
	{mso-style-priority:99;=0A=
	color:blue;=0A=
	text-decoration:underline;}=0A=
a:visited, span.MsoHyperlinkFollowed=0A=
	{mso-style-priority:99;=0A=
	color:purple;=0A=
	text-decoration:underline;}=0A=
span.EmailStyle17=0A=
	{mso-style-type:personal-compose;=0A=
	font-family:"Calibri","sans-serif";=0A=
	color:windowtext;}=0A=
.MsoChpDefault=0A=
	{mso-style-type:export-only;}=0A=
@page WordSection1=0A=
	{size:612.0pt 792.0pt;=0A=
	margin:72.0pt 72.0pt 72.0pt 72.0pt;}=0A=
div.WordSection1=0A=
	{page:WordSection1;}=0A=
--></style>=0A=
      <div class=3D"WordSection1">=0A=
        <p class=3D"MsoNormal">The string on 1.5v recharging demonstrated=
=0A=
          that some of you gurus are multitalented(sp?). So............<o:p=
></o:p></p>=0A=
        <p class=3D"MsoNormal">The batteries in our domestic cordless=0A=
          phones are giving up.<o:p></o:p></p>=0A=
        <p class=3D"MsoNormal">They are AAA Nickel Metal Hydride 550mAh.<o:=
p></o:p></p>=0A=
        <p class=3D"MsoNormal">Looking on eBay, most similar rechargeable=
=0A=
          AAA phone batteries are around 1500mAh. Nothing less than=0A=
          700mAh.<o:p></o:p></p>=0A=
        <p class=3D"MsoNormal">Can I stick in the highest rated that I can=
=0A=
          find, 1800mAh, and expect good results? Or does the higher mAh=0A=
          level imply some level of something that the phones=92 chargers=
=0A=
          won=92t manage???<o:p></o:p></p>=0A=
        <p class=3D"MsoNormal">(The charger says =93Output: 6v. 150mAh=94)<=
o:p></o:p></p>=0A=
        <p class=3D"MsoNormal">Simon<o:p></o:p></p>=0A=
      </div>=0A=
      <br>=0A=
    </blockquote>=0A=
    <br>=0A=
  =0A=
=0A=
</body></html>=

--_45B6A83A-7312-A35B-BAEF-F45BE7D76B02_--

--===============9128824744593942712==
Content-Transfer-Encoding: 7bit
Content-Disposition: inline

[email-masked]

--===============9128824744593942712==--

---

From: Bob Spidell <[email-masked]>
Date: Thu, 4 Jun 2015 15:36:44 +0000 (UTC)

--===============4276615391335753316==
	boundary="----=_Part_14754991_964075150.1433432204400"

------=_Part_14754991_964075150.1433432204400
Content-Transfer-Encoding: 7bit

Ah, yeah. Didn't catch that (although it's probably a single 6V battery with 4 internal 1.5V cells). 

1.5V would not be sufficient to power a radio signal suitable for even a portable phone. 

Bob 

----- Original Message -----

Hi 
Presumably there are 4 1.5 Volt cells in the phone that are connected in series. 4 * 1.5 = 6, voila. 

Per 

The mAH is a rating of how much current the battery can supply for how long: 

'milli Amp Hour' 

Get the highest rated you can find/afford; though the rating on the Chinese knock-offs--I think most of them are--seems to be overstated. The load--how much current will be used--is determined by the circuit on the phone. 

The statement on the charger makes no sense; applying 6V to a 1.5V battery would cook it in short order (putting 48V on a car battery would boil the electrolyte; creating a major mess and possibly an explosion). I suspect it's a nominal rating; i.e. it will put out 150mAH at 6v, but only needs about, oh, 2V or less to charge the batteries and would supply 450mAH at that voltage. 

E (voltage) = I (current) * R (resistance). Plug in any 2 known values--and use a little algebra if necessary--and you'll get the third. 

Bob 

------=_Part_14754991_964075150.1433432204400
Content-Transfer-Encoding: 7bit

<html><body><div style="font-family: Arial; font-size: 12pt; color: #000000"><div>Ah, yeah.&nbsp; Didn't catch that (although it's probably a single 6V battery with 4 internal 1.5V cells).&nbsp; </div><div><br></div><div>1.5V would not be sufficient to power a radio signal suitable for even a portable phone.<br></div><div><br></div><div>Bob<br></div><div><br></div><hr id="zwchr"><div style="color:#000;font-weight:normal;font-style:normal;text-decoration:none;font-family:Helvetica,Arial,sans-serif;font-size:12pt;"><br><div><br></div>

  <div><div style="font-family: Calibri,sans-serif; font-size: 11pt;">Hi<br>Presumably there are 4 1.5 Volt cells in the phone that are connected in series. 4 * 1.5 = 6, voila.<br><div><br></div>Per<br><div><br></div></div></div><hr><div><br></div>
    The mAH is a rating of how much current the battery can supply for
    how long:<br>
    <br>
    'milli Amp Hour'<br>
    <br>
    Get the highest rated you can find/afford; though the rating on the
    Chinese knock-offs--I think most of them are--seems to be
    overstated.&nbsp; The load--how much current will be used--is determined
    by the circuit on the phone.<br>
    <br>
    The statement on the charger makes no sense; applying 6V to a 1.5V
    battery would cook it in short order (putting 48V on a car battery
    would boil the electrolyte; creating a major mess and possibly an
    explosion).&nbsp; I suspect it's a nominal rating; i.e. it will put out
    150mAH at 6v, but only needs about, oh, 2V or less to charge the
    batteries and would supply 450mAH at that voltage.<br>
    <br>
    E (voltage) = I (current) * R (resistance).&nbsp; Plug in any 2 known
    values--and use a little algebra if necessary--and you'll get the
    third.<br>
    <br>
    Bob<br>
    <br>
    <br>
    <br><br class="moz-cite-prefix"></div><div><br></div></div></body></html>
------=_Part_14754991_964075150.1433432204400--

--===============4276615391335753316==
Content-Transfer-Encoding: 7bit
Content-Disposition: inline

[email-masked]

--===============4276615391335753316==--