[Shotimes] how do flashers work?
James F. Ryan III
av8r567@optonline.net
Thu, 07 Jul 2005 15:34:38 -0400
> Then please help me understand. LED's put out much more light with a
> lot less electricity.
Absolutely correct. LED's are MUCH more efficient at converting heat into
light than their incandescent counterparts. That's just technology, my
friend, not black magic.
> They also require a resister in-line to make them equal the resistance
> of the older incandescent bulb.
No. They require a resistor to limit the current so they don't damage
themselves.
> If they have much higher
> resistance, then why do they light up brighter and quicker with less
> juice?
You struck upon the very definition of a SEMI-conductor - a device that can
act as both a conductor and an insulator (but not at the same time).
Normally it has a very HIGH resistance and acts like an INSULATOR. However,
when you forward-bias the device (connect + battery to + lead of diode,
and - battery to - lead of diode) it will magically become a CONDUTOR at a
very low voltage of approx 0.7V. Now the LED/diode has a very LOW
resistance and must be protected with a properly sized current-limiting
resistor.
I thought the higher the resistance, the higher the ohms of
> resistance?
Yup.
>
> Just asking
>
> Don
>
> James F. Ryan III wrote:
>
> >>The LED's have a much lower resistance to electricity as I understand
> >>it, thus it is like opening up a water faucet from a slow drip to
> >>flood. Things move faster! :)
> >>
> >>
> >
> >LED's have a MUCH HIGHER resistance. High resistance = not a good
conductor
> >= very little current flow.
> >
> >LED's and diodes are classified as SEMI-conductors (that's an easy memory
> >aid).
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