I gotta get my calculator batteries replaced, my answers are relly
different...so I must be dooing something wrong....here is what I did...
231 cu in /gallon divided by 1728 cu in / cu ft = 0.1336 cu ft / min
assuming a gallon per minute. So if I divide that by 60 seconds per
minute to get 0.0022 ft^3/second. Then I set that equal to vent area
opening and column of air length. so at 0.1 inches in diameter the vent
cross sectional area is 0.0001 ft^2. so the column of air is 40.34 ft
tall. that must all enter through the vent in 1 minute so the speed is
about 40 ft per minute. Or abotu 0.6732 ft /sec. That is about 0.986 mph....
I havent done much math lately so this is probably really farkled. Since
the flow is so small, I did not account for reynols number effects,
compressibility effects or ...If the pressure diferential got up a bit
then the flow could be supersonic and that limits the amount of mass
that can flow theough the vent.
In any case, I just made mine -6 AN and said to hell with it...
mayf
Benn wrote:
>Hmm. I come up with 60 mph for .1" diameter hole at one gallon per
>minute (231 cubic inches per minute through 0.0079 square inch
>opening)...
>Benn
>
>----- Original Message -----
>From: "John Burk" <joyseydevil@comcast.net>
>To: "land-speed" <land-speed@autox.team.net>
>Sent: Thursday, January 05, 2006 9:40 PM
>Subject: Re: Fuel / Air Flow
>
>
>
>
>>Dick - These are the air speed through a hole to replace 1 gallon of
>>
>>
>fuel a
>
>
>>minute:
>>
>>.1" ----1668 mph
>>1/8" --1091 mph
>>1/4" --267 mph
>>3/8" --119 mph
>>1/2" --66 mph
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