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That is kind of what I thought. So how do I know which bearing needs to move
so that they are in this full contact position? Is this a press job, or
gentle hammer movement?
TIA,
Clayton
From: Osborne, Paul [mailto:paul@ece.rochester.edu]
Sent: Sunday, June 07, 2015 5:41 PM
To: crk@godblessthe.us
Subject: Re: [Mgs] mga MkII deluxe front wheel spindle distance piece
the per pose of the distance piece is to lock if you will the inter and
outer bearings together on the shaft. This makes them stronger as unit and
does not introduce and side thrust on the bearings. There should be a few
spacer washers to give the hub and end float of a few thousands.
paul
Paul Osborne
Department of Electrical and Computer Eng.
University of Rochester
201 Hopeman Building RC
Rochester NY 14627
585-275-5226
On Jun 7, 2015, at 6:39 PM, Clayton Kirkwood via Mgs <mgs@autox.team.net
Hi. In disassembling my front suspension, I ran across something for which
the manual has no input other to insert the distance piece which is the long
cylindrical one end chamfered piece between the inner and outer bearings.
When all is assembled, should the distance piece be a close fit between the
two bearing or is there supposed to be lots of slack? I ask because one
assembly came off with lots of longitudinal movement for the distance piece,
while the other side disassembled leaving the inner bearing on the spindle
and the distance piece coming out of the hub. I am assuming that the
distance is supposed to be a tight fit, and that the hub which came off with
bearings intact, slipped one of the bearings enough for the distance piece
to bounce around inside.
TIA,
Clayton
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</o:shapelayout></xml><![endif]--></head><body lang=3DEN-US link=3Dblue =
vlink=3Dpurple><div class=3DWordSection1><p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri",sans-serif;color:#1F497D'=
>That is kind of what I thought. So how do I know which bearing needs to =
move so that they are in this full contact position? Is this a press =
job, or gentle hammer movement?<o:p></o:p></span></p><p =
class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri",sans-serif;color:#1F497D'=
>TIA,<o:p></o:p></span></p><p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri",sans-serif;color:#1F497D'=
><o:p> </o:p></span></p><p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri",sans-serif;color:#1F497D'=
>Clayton<o:p></o:p></span></p><p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri",sans-serif;color:#1F497D'=
><o:p> </o:p></span></p><div><div =
style=3D'border:none;border-top:solid #E1E1E1 1.0pt;padding:3.0pt 0in =
0in 0in'><p class=3DMsoNormal><b><span =
style=3D'font-size:11.0pt;font-family:"Calibri",sans-serif'>From:</span><=
/b><span style=3D'font-size:11.0pt;font-family:"Calibri",sans-serif'> =
Osborne, Paul [mailto:paul@ece.rochester.edu] <br><b>Sent:</b> Sunday, =
June 07, 2015 5:41 PM<br><b>To:</b> =
crk@godblessthe.us<br><b>Subject:</b> Re: [Mgs] mga MkII deluxe front =
wheel spindle distance piece<o:p></o:p></span></p></div></div><p =
class=3DMsoNormal><o:p> </o:p></p><p class=3DMsoNormal>the per pose =
of the distance piece is to lock if you will the inter and outer =
bearings together on the shaft. This makes them stronger as unit and =
does not introduce and side thrust on the bearings. There should =
be a few spacer washers to give the hub and end float of a few =
thousands. <o:p></o:p></p><div><p =
class=3DMsoNormal><o:p> </o:p></p></div><div><p =
class=3DMsoNormal>paul<o:p></o:p></p></div><div><p =
class=3DMsoNormal><o:p> </o:p></p></div><div><p =
class=3DMsoNormal><o:p> </o:p></p><div><div><p =
class=3DMsoNormal><span class=3Dapple-style-span><span =
style=3D'color:black'>Paul Osborne</span></span><span =
style=3D'color:black'><br><span class=3Dapple-style-span>Department of =
Electrical and Computer Eng.</span><br><span =
class=3Dapple-style-span>University of Rochester </span><br><span =
class=3Dapple-style-span>201 Hopeman Building RC</span><br><span =
class=3Dapple-style-span>Rochester NY 14627</span><br><span =
class=3Dapple-style-span>585-275-5226</span></span><span =
style=3D'font-family:"Helvetica",sans-serif;color:black'><o:p></o:p></spa=
n></p></div><div><p class=3DMsoNormal><span =
style=3D'font-family:"Helvetica",sans-serif;color:black'><o:p> </o:p=
></span></p></div><p class=3DMsoNormal><o:p> </o:p></p></div><p =
class=3DMsoNormal><o:p> </o:p></p><div><div><p class=3DMsoNormal>On =
Jun 7, 2015, at 6:39 PM, Clayton Kirkwood via Mgs <<a =
href=3D"mailto:mgs@autox.team.net";>mgs@autox.team.net</a>> =
wrote:<o:p></o:p></p></div><p =
class=3DMsoNormal><br><br><o:p></o:p></p><blockquote =
style=3D'margin-top:5.0pt;margin-bottom:5.0pt'><div><div><p =
class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri",sans-serif'>Hi. In =
disassembling my front suspension, I ran across something for which the =
manual has no input other to insert the distance piece which is the long =
cylindrical one end chamfered piece between the inner and outer =
bearings. When all is assembled, should the distance piece be a close =
fit between the two bearing or is there supposed to be lots of slack? I =
ask because one assembly came off with lots of longitudinal movement for =
the distance piece, while the other side disassembled leaving the inner =
bearing on the spindle and the distance piece coming out of the hub. I =
am assuming that the distance is supposed to be a tight fit, and that =
the hub which came off with bearings intact, slipped one of the bearings =
enough for the distance piece to bounce around =
inside.<o:p></o:p></span></p></div><div><p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri",sans-serif'> <o:p></=
o:p></span></p></div><div><p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri",sans-serif'>TIA,<o:p></o:=
p></span></p></div><div><p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri",sans-serif'> <o:p></=
o:p></span></p></div><div><p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri",sans-serif'>Clayton<o:p><=
/o:p></span></p></div><p class=3DMsoNormal><span =
style=3D'font-size:10.5pt;font-family:"Helvetica",sans-serif'>___________=
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