Jim Barrett wrote:
>
> I hope I am calculating correctly on caster. My theory is that,
> (assuming zero camber to start), if one could turn the spindle 90 degrees
> then the "camber" would be the caster angle. Therefore if I turn the
> spindle 22 1/2 degrees the camber angle would be 1/4 of the caster.
> That is why I did the 4x calculation.
> I have a very expensive alignment set...
***********************
Jim,
It's clear that you've spared no expense with your alignment set. I'm
impressed. Think that your 4X rule might stand a bit of refinement
tho. I suspect that coupling between camber and caster is not a linear
function of steering angle but varies with the Sine of steering angle.
Mathematically it would look something like this:
Caster = Measured_camber X sin(Steering_angle)
If this is correct, then, for a steering angle of 22.5 degrees,
Caster = Measured_camber X sin(22.5)
= Measured_camber X 0.38
The 4X rule would then become a 1/0.38 = 2.6X rule. Note also that in
the limit, for an angle of 90 degrees, Sin(90) = 1 and camber = caster.
Don't take this as gospel. I haven't been through the analysis to say
that its correct or otherwise. It just looks right to me intuitively.
--
Intuitively yours, Will Seay - B382001570 - wseay@sprynet.com
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