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Re: [Healeys] Electrical Question - OR Circuit

To: "Alan Seigrist" <healey.nut@gmail.com>
Subject: Re: [Healeys] Electrical Question - OR Circuit
From: "Johnsen, Bernard" <bernard.johnsen@ngc.com>
Date: Wed, 18 Feb 2009 06:58:54 -0600
Alan - You don't need a relay to accomplish what you want. All you need
are two silicon diodes (rectifiers).They must have a current capacity
that is higher than the circuit you wish to drive. Hook up is as follows
(Assuming negative ground).
        The Anode of diode 1 is connected to "input 1". Anode of diode 2
connected to "input 2". The Cathodes of the two diodes are connected
together and they are the "output".
        For positive ground, reverse the diode polarity.

        - Bernie Johnsen 1967 BJ8

-----Original Message-----
From: healeys-bounces@autox.team.net
[mailto:healeys-bounces@autox.team.net] On Behalf Of Alan Seigrist
Sent: Tuesday, February 17, 2009 10:41 PM
To: andy pole
Cc: healeys@autox.team.net
Subject: Re: [Healeys] Electrical Question - OR Circuit

Andy -

Great, thank you, this is helpful.  I will need to use Relays to do the
switching (as the circuits are auto switched) but this helps me
mentally.

Best,

Alan

'52 A90
'53 BN1
'64 BJ8


On Wed, Feb 18, 2009 at 11:38 AM, andy pole <ampole@hotmail.com> wrote:

>  Alan
>
> To put it really simply you would not need a relay as you will be
> using switches to drive the relay, you can do it with just 2 way
> switches wired in parallel, (parrallel is OR, series is AND)
>
> input 1 on first switch (2 way switch) input 2 on second switch (2 way

> switch)
>
> then for arguments sake wire both sides of the switch to a bulb, then
> earth the bulb.
>
> Either switches will turn on the bulb, or both together, if both are
> off the bulb will be off
>
> you could do it with a semiconductor logic gate, but 2 switches would
> do
>
> hope that makes sense
>
> Andy
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