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Total 8 documents matching your query.

1. Healey and car related (score: 1): Author: <pennell@cox.net>; Date: Tue, 3 Jan 2006 21:52:15 -0500; On a recent trip alone to NC I had plenty of time to think about stuff. Most of it not too productive - just staring down the highway. For some reason the following came to me. Suppose you take a ca; /html/healeys/2006-01/msg00128.html (7,576 bytes)
2. Re: Healey and car related (score: 1): Author: RobertH148@aol.com; Date: Tue, 3 Jan 2006 22:33:31 EST; The answer is 0". The steering wheel will be turned slightly in the opposite direction and the car will go straight with no displacement. Bob Humphreys; /html/healeys/2006-01/msg00130.html (7,062 bytes)
3. RE: Healey and car related (score: 1): Author: healeyolic <healey6@optonline.net>; Date: Tue, 03 Jan 2006 22:34:29 -0500; That must have been one VERY lonely and boring trip. John Sims, BN6 Aberdeen, NJ www.healey6.com Listers, On a recent trip alone to NC I had plenty of time to think about stuff. Most of it not too pr; /html/healeys/2006-01/msg00131.html (8,228 bytes)
4. Re: Healey and car related (score: 1): Author: Eric (Rick) Wilkins <wilko2@cox.net>; Date: Tue, 3 Jan 2006 19:56:18 -0800; I'm no math wiz, but assuming the steering instantly were to change from zero to 1/8" and there would be no scrubbing, I get about 7.8" Wilko San Diego; /html/healeys/2006-01/msg00133.html (8,164 bytes)
5. Re: Healey and car related (score: 1): Author: Eric (Rick) Wilkins <wilko2@cox.net>; Date: Tue, 3 Jan 2006 20:02:38 -0800; Obviously I'm no math wiz... I need to move a decimal place and say about 0.78"; /html/healeys/2006-01/msg00134.html (8,514 bytes)
6. Re: Healey and car related (score: 1): Author: Roland Wilhelmy <rwil@sbcglobal.net>; Date: Tue, 03 Jan 2006 21:17:55 -0800; Here's my entry: front of tire moves 1/8 inch left, so we have a triangle about 13.5" (the tire's radius) on two sides and 1/8" on the third side. arc tan of .125/13.5 is 0.53 degrees. if the diamete; /html/healeys/2006-01/msg00138.html (8,280 bytes)
7. RE: Healey and car related (score: 1): Author: "Len and/or Marge" <thehartnetts@earthlink.net>; Date: Tue, 3 Jan 2006 22:30:46 -0800; Here are my calculations without any knowledge of 'arc tangents', etc. : Diameter of tire = 24" Radius = 12" 1/8" or .125" at 12" Circumference = Pi d 3.141259 times 24" = 75.39816" 75.39816 divided; /html/healeys/2006-01/msg00139.html (8,472 bytes)
8. Re: Healey and car related (score: 1): Author: Tom Simkins <ah1006@verizon.net>; Date: Wed, 4 Jan 2006 17:26:14 -0800 (PST); I'm no mathemetician either, but, it seems to me that if a point on the front of the tire exactly 90 deg from a point on the bottom of the tire is 1/8 in to the side of the point on the bottom, when; /html/healeys/2006-01/msg00180.html (8,646 bytes)

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