OK, I'll take a whack at it. Hydraulics seem so simple, until you start
to work with them in the real world...
If you have a 1 square inch piston to which you apply 10 lbs. of force
you get 10 lbs. per square inch (psi). If you apply that 10 psi to a 1
square inch piston, you get 10 lbs of force back out.
If you take the same setup and apply the 10 psi to a 0.5 square inch
piston you are now getting 10 lbs per 1/2 square inch which is 20 psi and
you get 20 lbs. of force out of the system.
Works the same way in reverse, the 10 psi applied to a 2 square inch
piston gives 10 lbs per 2 square inches which is 5 lbs. per square inch
and you get 5 lbs of force out of the system.
Bill 70 GT-6+
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