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## RE: Re[2]: What differential?

 To: triumphs@autox.team.net ('trumppa') RE: Re[2]: What differential? knystrom@NCSCTC01ES.ntc.nokia.com (Nystrom Kim NTC/Espoo) Tue, 01 Oct 1996 10:12:01 +0300 Nokia Telecommunications
 ```Thanks for the formula! But I still can't figure it out. Try it yourselves with the figures I got: DR=(RPM x TD) / (MPH x 336) TD=22.653 (175/70, 13" tires) RPM=4500, KPH=112 (=69.9 Am.MPH, =60.44 Brit.MPH) => DR (Am) = 4.34, DR (Br) = 5.02 RPM=3000, KPH=80 (=49.7 Am.MPH, 43.17 Br.MPH) => DR (Am) = 4.06 RPM=1000, KPH=28 => DR (Am) = 3.87 It makes you wonder, doesn't it....? Maybe I have a changing DR ;-) I guess I'll have to try the string method as soon as it stops raining. Thanks a lot, Kim N from a cold AND wet Helsinki, Finland ---------- ** From: Kevin Andrews ** ** In an article in our newsletter, Pat McMullen wrote about tire sizes and what ** speed you are traveling with different sizes.So he had a formula. This formula ** will not work on automatic tranies.You need 3 of these 4 things. ** 1.RPM ** 2.TD= tire diameter ** 3.MPH ** 4.DR= drive ratio(final drive) ** RPM is self explanitory,you have tire size but need to get tire diameter(ex. ** 205 65 R15 205 is tread width in millimeters.Convert to inches(205 times ** .0394=8.077). The 65 represents tire profile, a percentage of the tread ** width.So 65% of 8.077 is 5.25 inches. Now rim size is 15 inches in diameter. ** So you add that to the tire profile twice to get tire diameter.(5.25+15+5.25=25.5 ** inches). Now you got MPH. Now to figure DR you use this formula. ** DR = RPM x TD divided by MPH x 336 (336 is a constant and ** will never change) ** Hope this will help. It was a great article by Pat. ** Kevin Andrews ** 68 TR-250(CD7766L) ** Siler City, NC ** ```
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