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Re[2]: What differential?

 To: triumphs@autox.team.net Re[2]: What differential? Bschwartz@encad.com (Barry Schwartz) Tue, 1 Oct 1996 06:38:13 -0700
 ```> Tony wrote > The ratio is determined by the number of teeth in the pinion gear and > how many teeth it has to travel on the similiarly beveled ring gear to > make one complete revolution and then how many times the pinion gear > has to turn to make the ring gear make one complete revolution to > complete the final drive. > Sorry, I just don't see anyway you can determine the ratio considering > the variation in tire sizes and the variation of non-stock drive shafts, > like mine. > Anybody care to elaborate. Maybe I am wrong, but I don't think so. > Regards, --------------------------------------------------------------------------- You are correct in that the ratio is determined by the number of teeth on the ring gear vs the number of teeth on the pinion, and thats the ideal and sure way to determine said ratio. However, you are incorrect in claming that tire size and driveshaft size screws up the formula. A revoloution is a revolution no mater how "big" or "small" its diameter, and a ratio in this case is a direct relation between the number of times the driveshaft turns vs the number of times the axle turns. If the ring gear (connected to the axle) turns 4 times, it's corresponding wheel turns 4 times, no matter what the size. The same holds true for the drive-shaft connected to the pinion gear. The only anomaly in this are the "spider" gears, which allow the wheels to differentiate (differental) when cornering. Hope that clear's things up a bit- Barry Schwartz Bschwartz@encad.com Bschwart@pacbell.net 63' Spitfire, 72'-V6 Spitfire 70'GT6+ ```
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