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Re: [TR] WAS (no subject) NOW rule of 9 valve adjustment

To: Randall <TR3driver@ca.rr.com>
Subject: Re: [TR] WAS (no subject) NOW rule of 9 valve adjustment
From: Paul Dorsey <dorpaul1@gmail.com>
Date: Mon, 5 Nov 2018 17:46:30 -0500
Cc: "Triumph list Team.net" <triumphs@autox.team.net>
Delivered-to: mharc@autox.team.net
Delivered-to: triumphs@autox.team.net
References: <CAFU8DPv1pDnY1STzyHhSHwryMGDfG1t_6ke1vw49gNZyHaUYww@mail.gmail.com> <BE0D873B83A14AAE85875233911F9E66@RYPC>
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Got it.

On Mon, Nov 5, 2018 at 4:13 PM Randall <TR3driver@ca.rr.com> wrote:

>
> >       Sorry for the interlude as I was getting the house
> > painted, but, I am now on the tr 3 again.  And I was
> > adjusting the valves using the 'rule of 9', which seems
> > simple enough.  AT TDC valve no.1 is adjusted because valve 8
> > is descending, right?  Valve no. 6 is adjusted when valve 3
> > is open, That is 1+8=9 and 6+3=9, respectively right?  Well,
> > how concerned should I be that valve 8 and valve 3 (in this
> > example) are fully open?
>
> Paul, I'm not sure your question here got answered.  Ideally, the other
> valve should be fully open, however it doesn't really matter.  As long as
> it
> is partially open, the opposite valve will be on the base circle.  Hence
> fully closed and available for adjustment.
>
> -- Randall
>
>

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<div>Got it.</div><div><br><div class=3D"gmail_quote"><div dir=3D"ltr">On M=
on, Nov 5, 2018 at 4:13 PM Randall &lt;<a href=3D"mailto:TR3driver@ca.rr.co=
m">TR3driver@ca.rr.com</a>&gt; wrote:<br></div><blockquote class=3D"gmail_q=
uote" style=3D"margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1e=
x"><br>
&gt;=C2=A0 =C2=A0 =C2=A0 =C2=A0Sorry for the interlude as I was getting the=
 house <br>
&gt; painted, but, I am now on the tr 3 again.=C2=A0 And I was <br>
&gt; adjusting the valves using the &#39;rule of 9&#39;, which seems <br>
&gt; simple enough.=C2=A0 AT TDC valve no.1 is adjusted because valve 8 <br=
>
&gt; is descending, right?=C2=A0 Valve no. 6 is adjusted when valve 3 <br>
&gt; is open, That is 1+8=3D9 and 6+3=3D9, respectively right?=C2=A0 Well, =
<br>
&gt; how concerned should I be that valve 8 and valve 3 (in this <br>
&gt; example) are fully open?<br>
<br>
Paul, I&#39;m not sure your question here got answered.=C2=A0 Ideally, the =
other<br>
valve should be fully open, however it doesn&#39;t really matter.=C2=A0 As =
long as it<br>
is partially open, the opposite valve will be on the base circle.=C2=A0 Hen=
ce<br>
fully closed and available for adjustment.<br>
<br>
-- Randall<br>
<br>
</blockquote></div></div>

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