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Re: [Healeys] Hot & Cold Brake Wires

To: "R. Lindsay" <050.rpl@gmail.com>
Subject: Re: [Healeys] Hot & Cold Brake Wires
From: Michael Salter via Healeys <healeys@autox.team.net>
Date: Sun, 11 Jul 2021 16:41:23 -0400
Cc: Healey List <healeys@autox.team.net>
Delivered-to: mharc@autox.team.net
Delivered-to: healeys@autox.team.net
References: <618226AC-AAE8-4738-BAC2-96D4A1ABC38B@gmail.com>
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You are correct.  The live side is the solid green. Live with ignition on.

M

On Sun., Jul. 11, 2021, 4:22 p.m. R. Lindsay via Healeys, <
healeys@autox.team.net> wrote:

> Is there a =E2=80=9Chot=E2=80=9D or =E2=80=9Ccold=E2=80=9D side to the wi=
ring of the brake switch in a 67
> BJ8.  I can see there are two wires to the switch, Green and Green/Purple=
.
> I presume the current enters the switch off of one wire and leaves the
> switch off the other.  I would guess the current comes to the switch from
> the green wire and exits via the green/purple, but its only a guess.
> Further the =E2=80=9Chot=E2=80=9D side, I=E2=80=99d guess, is the one tha=
t takes the current to the
> switch (green.)
>
> Is my thinking correct, wrong or neither, i.e., there is no hot or cold
> side.  Thank you for your input.
>
> Price Lindsay
>
> Sent from my iPad
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<div dir=3D"auto">You are correct.=C2=A0 The live side is the solid green. =
Live with ignition on.<div dir=3D"auto"><br></div><div dir=3D"auto">M</div>=
</div><br><div class=3D"gmail_quote"><div dir=3D"ltr" class=3D"gmail_attr">=
On Sun., Jul. 11, 2021, 4:22 p.m. R. Lindsay via Healeys, &lt;<a href=3D"ma=
ilto:healeys@autox.team.net">healeys@autox.team.net</a>&gt; wrote:<br></div=
><blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1=
px #ccc solid;padding-left:1ex">Is there a =E2=80=9Chot=E2=80=9D or =E2=80=
=9Ccold=E2=80=9D side to the wiring of the brake switch in a 67 BJ8.=C2=A0 =
I can see there are two wires to the switch, Green and Green/Purple.=C2=A0 =
I presume the current enters the switch off of one wire and leaves the swit=
ch off the other.=C2=A0 I would guess the current comes to the switch from =
the green wire and exits via the green/purple, but its only a guess.=C2=A0 =
Further the =E2=80=9Chot=E2=80=9D side, I=E2=80=99d guess, is the one that =
takes the current to the switch (green.)<br>
<br>
Is my thinking correct, wrong or neither, i.e., there is no hot or cold sid=
e.=C2=A0 Thank you for your input. <br>
<br>
Price Lindsay<br>
<br>
Sent from my iPad<br>
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</blockquote></div>

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