Re: [Healeys] Hot & Cold Brake Wires

[Elton S via Healeys <healeys@autox.team.net>]

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 According to the wiring diagram, the green-purple goes to the brakelights.
The green comes from the fusebox.
Elton

On Sun, Jul 11, 2021 at 4:22 PM R. Lindsay via Healeys <
healeys@autox.team.net> wrote:

> Is there a =E2=80=9Chot=E2=80=9D or =E2=80=9Ccold=E2=80=9D side to the wi=
ring of the brake switch in a 67
> BJ8.  I can see there are two wires to the switch, Green and Green/Purple=
.
> I presume the current enters the switch off of one wire and leaves the
> switch off the other.  I would guess the current comes to the switch from
> the green wire and exits via the green/purple, but its only a guess.
> Further the =E2=80=9Chot=E2=80=9D side, I=E2=80=99d guess, is the one tha=
t takes the current to the
> switch (green.)
>
> Is my thinking correct, wrong or neither, i.e., there is no hot or cold
> side.  Thank you for your input.
>
> Price Lindsay
>
> Sent from my iPad
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<div dir=3D"ltr">=C2=A0According to the wiring diagram, the green-purple go=
es to the brakelights. The green comes from the fusebox.<div>Elton</div></d=
iv><br><div class=3D"gmail_quote"><div dir=3D"ltr" class=3D"gmail_attr">On =
Sun, Jul 11, 2021 at 4:22 PM R. Lindsay via Healeys &lt;<a href=3D"mailto:h=
ealeys@autox.team.net">healeys@autox.team.net</a>&gt; wrote:<br></div><bloc=
kquote class=3D"gmail_quote" style=3D"margin:0px 0px 0px 0.8ex;border-left:=
1px solid rgb(204,204,204);padding-left:1ex">Is there a =E2=80=9Chot=E2=80=
=9D or =E2=80=9Ccold=E2=80=9D side to the wiring of the brake switch in a 6=
7 BJ8.=C2=A0 I can see there are two wires to the switch, Green and Green/P=
urple.=C2=A0 I presume the current enters the switch off of one wire and le=
aves the switch off the other.=C2=A0 I would guess the current comes to the=
 switch from the green wire and exits via the green/purple, but its only a =
guess.=C2=A0 Further the =E2=80=9Chot=E2=80=9D side, I=E2=80=99d guess, is =
the one that takes the current to the switch (green.)<br>
<br>
Is my thinking correct, wrong or neither, i.e., there is no hot or cold sid=
e.=C2=A0 Thank you for your input. <br>
<br>
Price Lindsay<br>
<br>
Sent from my iPad<br>
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</blockquote></div>

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