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Re: [Healeys] Hot & Cold Brake Wires

To: Elton S <eps2660@gmail.com>
Subject: Re: [Healeys] Hot & Cold Brake Wires
From: Michael Oritt <michael.oritt@gmail.com>
Date: Sun, 11 Jul 2021 19:18:03 -0400
Cc: Healey List <healeys@autox.team.net>
Delivered-to: mharc@autox.team.net
Delivered-to: healeys@autox.team.net
References: <618226AC-AAE8-4738-BAC2-96D4A1ABC38B@gmail.com> <CAFKLAdiQb_VBBRgi7+LHdMHqJ+oXYCNWp4jEQYD4g+q9_Pxr7Q@mail.gmail.com>
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Sorry, I did not read the question carefully and yes the wiring is "hot"
and "cold" as stated by others.

Best--Michael Oritt

On Sun, Jul 11, 2021 at 4:54 PM Elton S via Healeys <healeys@autox.team.net=
>
wrote:

>  According to the wiring diagram, the green-purple goes to the
> brakelights. The green comes from the fusebox.
> Elton
>
> On Sun, Jul 11, 2021 at 4:22 PM R. Lindsay via Healeys <
> healeys@autox.team.net> wrote:
>
>> Is there a =E2=80=9Chot=E2=80=9D or =E2=80=9Ccold=E2=80=9D side to the w=
iring of the brake switch in a 67
>> BJ8.  I can see there are two wires to the switch, Green and Green/Purpl=
e.
>> I presume the current enters the switch off of one wire and leaves the
>> switch off the other.  I would guess the current comes to the switch fro=
m
>> the green wire and exits via the green/purple, but its only a guess.
>> Further the =E2=80=9Chot=E2=80=9D side, I=E2=80=99d guess, is the one th=
at takes the current to the
>> switch (green.)
>>
>> Is my thinking correct, wrong or neither, i.e., there is no hot or cold
>> side.  Thank you for your input.
>>
>> Price Lindsay
>>
>> Sent from my iPad
>> _______________________________________________
>> Support Team.Net http://www.team.net/donate.html
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>>
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>

--=20
Best--Michael

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<div dir=3D"ltr"><div class=3D"gmail_default" style=3D"color:#3333ff">Sorry=
, I did not read the question carefully and yes the wiring is &quot;hot&quo=
t; and &quot;cold&quot; as stated by others.</div><div class=3D"gmail_defau=
lt" style=3D"color:#3333ff"><br></div><div class=3D"gmail_default" style=3D=
"color:#3333ff">Best--Michael Oritt</div></div><br><div class=3D"gmail_quot=
e"><div dir=3D"ltr" class=3D"gmail_attr">On Sun, Jul 11, 2021 at 4:54 PM El=
ton S via Healeys &lt;<a href=3D"mailto:healeys@autox.team.net";>healeys@aut=
ox.team.net</a>&gt; wrote:<br></div><blockquote class=3D"gmail_quote" style=
=3D"margin:0px 0px 0px 0.8ex;border-left:1px solid rgb(204,204,204);padding=
-left:1ex"><div dir=3D"ltr">=C2=A0According to the wiring diagram, the gree=
n-purple goes to the brakelights. The green comes from the fusebox.<div>Elt=
on</div></div><br><div class=3D"gmail_quote"><div dir=3D"ltr" class=3D"gmai=
l_attr">On Sun, Jul 11, 2021 at 4:22 PM R. Lindsay via Healeys &lt;<a href=
=3D"mailto:healeys@autox.team.net"; target=3D"_blank">healeys@autox.team.net=
</a>&gt; wrote:<br></div><blockquote class=3D"gmail_quote" style=3D"margin:=
0px 0px 0px 0.8ex;border-left:1px solid rgb(204,204,204);padding-left:1ex">=
Is there a =E2=80=9Chot=E2=80=9D or =E2=80=9Ccold=E2=80=9D side to the wiri=
ng of the brake switch in a 67 BJ8.=C2=A0 I can see there are two wires to =
the switch, Green and Green/Purple.=C2=A0 I presume the current enters the =
switch off of one wire and leaves the switch off the other.=C2=A0 I would g=
uess the current comes to the switch from the green wire and exits via the =
green/purple, but its only a guess.=C2=A0 Further the =E2=80=9Chot=E2=80=9D=
 side, I=E2=80=99d guess, is the one that takes the current to the switch (=
green.)<br>
<br>
Is my thinking correct, wrong or neither, i.e., there is no hot or cold sid=
e.=C2=A0 Thank you for your input. <br>
<br>
Price Lindsay<br>
<br>
Sent from my iPad<br>
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</blockquote></div>
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</blockquote></div><br clear=3D"all"><div><br></div>-- <br><div dir=3D"ltr"=
 class=3D"gmail_signature"><font color=3D"#3333ff">Best--Michael</font></di=
v>

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