Hmmm, my take is as follows:
4.2 g's on 1900# is an average "push" of about 8000#, as you indicate.
If this amount of force (push, thrust, whatever) is applied evenly over
the 1320 feet, we have about (1320 x 8000) foot-# of work performed in
4.4 sec, or 2.4 million ft-#/sec. Divide this rate by 550 ft-#/sec
(which is one horsepower), and the result is about 4400 hp. Yow!
Benn
----- Original Message -----
From: "John Burk" <joyseydevil@comcast.net>
To: <land-speed@Autox.Team.Net>
Sent: Tuesday, January 04, 2005 10:54 AM
Subject: Re: Engine Config
> Dave - In reference to your doubts about a blown fuel drag engine
realy
> putting out the claimed hp do you agree with these numbers - Distance
fallen
> in 4.42 seconds at 1 G is 1/2 A (16) X seconds squared (4.42 X 4.42) =
312.58'
> - Average acceleration for 1320' in 4.42 seconds is 1320'/312.58' =
4.22 G's -
> The accelerating force for a 1900# object at 4.22 G's is 8018# - If
the engine
> is running for the entire time the equivalent of 332 mph (472.27
ft/sec) the
> hp is ft lb (472.27 ft X 8018 lb) per second (1) /550 = 6884.84 hp -
The true
> hp would be reduced some because the engine runs less than the
equivalent of
> 332 mph earlier in the run - Because the 6884.48 hp doesn't include
the aero
> drag (plenty) 6000 to 7000 hp can't be far off - John
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