The starter solenoid temporarily supplies 12 volts to the. Oil while the
starter is cranking.
As soon as you release the key that temporary 12 volts is disconnected and the
power to the coil is via the ballast resistor.
It sounds like you either have a bad ballast resistor or broken wiring to the
ballast resistor.
Temporarily add an alligator jumper across the two tabs on the resistor and see
if it starts. If it does start you have a bad resistor.
And if that does not work, start looking for lack of 12 volts INTO. The ballast
resistor.
From Don's iPhone 203-592-8427
Or 203-264-8301 home
> On Nov 20, 2019, at 4:20 PM, Joe Brown via Tigers <tigers@autox.team.net>
> wrote:
>
> 
> Hey,
>
> I'm trying to fire up my engine for the first time and I have a question.
> When I turn the key to the start position the engine turns over and fires up.
> But as soon as I let go of the key so that it returns to the run position it
> dies. It seems like the ignition system is only getting power when the key
> is in the start position.
>
> I'm a little confused by the wiring diagram. The white/blue wire from the
> solenoid goes to the coil and this would seem to imply that there should
> always be 12V on this wire when the key is in the run position. Is this
> correct? I'm only getting the 12V on this line when the key is in the start
> position.
>
> Any ideas?
>
> Thanks,
> Joe Brown
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>
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