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Joe
NO =E2=80=93 White / blue wire is the start position =
only =E2=80=93 feeds 12v to the coil =E2=80=93 no voltage when released
=20
White wire from ignition switch #2 post feeds through the Tach to the =
ballast resistor to the coil =E2=80=93 this is the run voltage.
=20
Hope that helps
Ron Fraser
=20
From: Tigers <tigers-bounces@autox.team.net> On Behalf Of Joe Brown via =
Tigers
Sent: Wednesday, November 20, 2019 4:20 PM
To: Tigers Den <Tigers@autox.team.net>
Subject: [Tigers] Starter Solenoid
=20
Hey,
=20
I'm trying to fire up my engine for the first time and I have a =
question. When I turn the key to the start position the engine turns =
over and fires up. But as soon as I let go of the key so that it =
returns to the run position it dies. It seems like the ignition system =
is only getting power when the key is in the start position.=20
=20
I'm a little confused by the wiring diagram. The white/blue wire from =
the solenoid goes to the coil and this would seem to imply that there =
should always be 12V on this wire when the key is in the run position. =
Is this correct? I'm only getting the 12V on this line when the key is =
in the start position. =20
=20
Any ideas?
=20
Thanks,
Joe Brown
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link=3D"#0563C1" vlink=3D"#954F72"><div class=3DWordSection1><p =
class=3DMsoNormal>Joe<o:p></o:p></p><p =
class=3DMsoNormal>=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=
=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 NO =E2=80=93 White / blue wire is the =
start position only =E2=80=93 feeds 12v to the coil =E2=80=93 no voltage =
when released<o:p></o:p></p><p class=3DMsoNormal><o:p> </o:p></p><p =
class=3DMsoNormal>White wire from ignition switch #2 post feeds through =
the Tach to the ballast resistor to the coil =E2=80=93 this is the run =
voltage.<o:p></o:p></p><p class=3DMsoNormal><o:p> </o:p></p><p =
class=3DMsoNormal>Hope that helps<o:p></o:p></p><p class=3DMsoNormal>Ron =
Fraser<o:p></o:p></p><p class=3DMsoNormal><o:p> </o:p></p><p =
class=3DMsoNormal><b>From:</b> Tigers =
<tigers-bounces@autox.team.net> <b>On Behalf Of </b>Joe Brown via =
Tigers<br><b>Sent:</b> Wednesday, November 20, 2019 4:20 =
PM<br><b>To:</b> Tigers Den =
<Tigers@autox.team.net><br><b>Subject:</b> [Tigers] Starter =
Solenoid<o:p></o:p></p><p class=3DMsoNormal><o:p> </o:p></p><div><p =
class=3DMsoNormal>Hey,<o:p></o:p></p><div><p =
class=3DMsoNormal><o:p> </o:p></p></div><div><p =
class=3DMsoNormal>I'm trying to fire up my engine for the first time and =
I have a question. When I turn the key to the start position the =
engine turns over and fires up. But as soon as I let go of the key =
so that it returns to the run position it dies. It seems like the =
ignition system is only getting power when the key is in the start =
position. <o:p></o:p></p></div><div><p =
class=3DMsoNormal><o:p> </o:p></p></div><div><p =
class=3DMsoNormal>I'm a little confused by the wiring diagram. The =
white/blue wire from the solenoid goes to the coil and this would seem =
to imply that there should always be 12V on this wire when the key is in =
the run position. Is this correct? I'm only getting the 12V =
on this line when the key is in the start =
position. <o:p></o:p></p></div><div><p =
class=3DMsoNormal><o:p> </o:p></p></div><div><p =
class=3DMsoNormal>Any ideas?<o:p></o:p></p></div><div><p =
class=3DMsoNormal><o:p> </o:p></p></div><div><p =
class=3DMsoNormal>Thanks,<o:p></o:p></p></div><div><p =
class=3DMsoNormal>Joe =
Brown<o:p></o:p></p></div></div></div></body></html>
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